Explain the equilibrium involving the dissolution of a solid in a liquid.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) When a solid solute is added to a liquid solvent,it dissolves until the solution becomes saturated. At this point,a dynamic equilibrium is established between the undissolved solid and the dissolved solute.
$Solute \text{ (solid)} \rightleftharpoons Solute \text{ (in solution)}$
At equilibrium,the rate of dissolution of the solid equals the rate of crystallization of the solute from the solution. The concentration of the solute in the solution remains constant at a given temperature.

Explore More

Similar Questions

At $25^{\circ} C$, the solubility product of a salt of $MX_{2}$ type is $3.2 \times 10^{-8}$ in water. The solubility (in $mol / L$) of $MX_{2}$ in water at the same temperature will be:

The solubility of $AgCl$ at $20\,^oC$ is $1.435 \times 10^{-3} \, g/L$. The solubility product of $AgCl$ is .......

The solubility product constants $(K_{sp})$ for some silver salts are given as: $AgCl = 2 \times 10^{-10}$,$AgBr = 5 \times 10^{-13}$,$Ag_2CO_3 = 8 \times 10^{-12}$,and $AgI = 8 \times 10^{-17}$. Which of the following salts has the highest solubility?

The $pH$ of a saturated solution of $Ca(OH)_2$ is $12.25$. Calculate its solubility product $(K_{sp})$.

The solubility of $CuBr$ is $2 \times 10^{-4} \ mol/L$ at $25 \ ^\circ C$. The $K_{sp}$ value for $CuBr$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo